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Move actual square setter to _set

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Eryn Wells 2017-10-11 20:24:09 -07:00
parent 387ccacb8d
commit a9a331df91
1 changed files with 10 additions and 5 deletions
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15
sudoku/__init__.py
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@ -143,10 +143,6 @@ class Sudoku:
return solver(self) return solver(self)
def set(self, x, y, value): def set(self, x, y, value):
idx = self._xy_to_idx(x, y)
if idx in self._clues:
raise SquareIsClue('Cannot set clue square ({},{})'.format(x, y))
if value not in self.possible_values: if value not in self.possible_values:
raise ValueError('{} not in set of possible values {}'.format(value, self.possible_values)) raise ValueError('{} not in set of possible values {}'.format(value, self.possible_values))
@ -156,8 +152,17 @@ class Sudoku:
if value in peers: if value in peers:
raise ValueExistsInPeers('{} already exists in the peer set for ({},{})'.format(value, x, y)) raise ValueExistsInPeers('{} already exists in the peer set for ({},{})'.format(value, x, y))
self._set(x, y, value)
def unset(self, x, y):
self._set(x, y, 0)
def _set(self, x, y, value):
idx = self._xy_to_idx(x, y)
if idx in self._clues:
raise SquareIsClue('Cannot set clue square ({},{})'.format(x, y))
self._board[idx] = value self._board[idx] = value
print('({},{}) <- {} (p:{}) {!r}'.format(x, y, value, peers, self)) print('({},{}) <- {} {!r}'.format(x, y, value, self))
def _xy_to_idx(self, x, y): def _xy_to_idx(self, x, y):
return y * self.row_size + x return y * self.row_size + x