Quick implement rows, columns, and square

This commit is contained in:
Eryn Wells 2017-10-07 12:24:41 -07:00
parent 2feef04ad9
commit f98a0f4f75

View file

@ -4,6 +4,7 @@
A Sudoku puzzle solver.
'''
import itertools
import math
class Sudoku:
@ -15,21 +16,41 @@ class Sudoku:
self.size = size
self.board = bytearray(b'\x00' * (size * size))
@property
def rows(self):
sz = self.size
return [range(i * sz, i * sz + sz) for i in range(sz)]
@property
def columns(self):
sz = self.size
sz2 = sz ** 2
return [range(i, sz2, sz) for i in range(sz)]
@property
def solved(self):
def _check_group(group):
values = sorted([self.board[i] for i in group])
is_complete = values == list(range(1, self.size+1))
return is_complete
sz = self.size
sz2 = sz ** 2
dim = int(math.sqrt(self.size))
rows = [range(i * sz, i * sz + sz) for i in range(sz)]
cols = [range(i, sz2, sz) for i in range(sz)]
# TODO: WIP
def square(self, x, y):
dim = int(math.sqrt(self.size))
if (x < 0 or x >= dim) or (y < 0 or y >= dim):
raise IndexError('Invalid coordinates for square: ({}, {})'.format(x, y))
offset_x = x * dim
offset_y = y * dim
def _range(i):
start = offset_x + i * self.size
return range(start, start + dim)
ranges = itertools.chain(*[_range(i) for i in range(dim)])
return ranges
def __str__(self):
field_width = len(str(self.size))
dim = int(math.sqrt(self.size))